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"曲率半径处处相等,摩擦系数点点为零"点译? 多谢! [Copy link] 中文

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Post time 2004-12-14 09:33:29 |Display all floors
横批: 又圆又滑

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Post time 2004-12-14 09:34:59 |Display all floors

Faints....

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Post time 2004-12-14 09:44:38 |Display all floors

曲率半径处处相等,摩擦系数点点为零"点译

same radius of curvature everywhere and zero friction coefficient every point.

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Post time 2004-12-14 09:45:04 |Display all floors

try

曲率半径处处相等,摩擦系数点点为零"点译? 多谢!
横批: 又圆又滑

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the curvature radius is always same;
the friction coefficient is always zero.

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Post time 2004-12-14 09:45:48 |Display all floors

round and smooth

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Post time 2004-12-14 09:47:21 |Display all floors

又圆又滑

no wonder you are round and smooth!

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Post time 2004-12-14 11:09:39 |Display all floors

well done, tks!

btw, loong, don't 笑里藏针ok?

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